What are the points of intersection between the graphs of the functions f(x) = x²(x + 1) and g(x) = x + 1?

The points of intersection of two functions are required.

The points of intersection are and .

The given functions are

Equating them with each other

Substitute the value in one of the functions.

The points of intersection are and .

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(x1,y1) = (1, 2)

(x2,y2) = (-1,0)

Step-by-step explanation:

Given: f(x) = x²(x + 1) and g(x) = x + 1

To find the intersection, then set functions equal to each other to solve for x first.

x²(x + 1) =  x + 1; divide by (x+1) from both sides

= 1; take the square root to both sides

x = ±1;

The graphs intersect at two points (x1,y1) and (x2,y2)

Use x=1

f(1) = x²(x + 1) = (1+1) = 2

g(1) = x + 1 = 1 + 1 = 2

(x1,y1) = (1, 2)

Use x= -1

f(-1) = x²(x + 1) = (-1+1) = 0

g(-1) = x + 1 = -1 + 1 = 0

(x2,y2) = (-1,0)

ok

step-by-step explanation:

the answer is b.

64

step-by-step explanation:

c=2πr=2·π·8≈64