Jordan is planning to buy a vehicle. He has the following choices. Type: sedan or SUV
Transmission: 5-speed or automatic
Color: red, blue, black, green, or silver
Top: sunroof or no sunroof

Jordan says that he has a total of 2 + 2 + 5 + 2, or 11, possible vehicle choices. What is Jordan’s error?
He should have multiplied the sum by 4.
He should have added only the choices for type and transmission.
He should have multiplied only the choices for type and transmission.
He should have multiplied the choices, instead of adding them.

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)

too many. (jk)

31 v bucks

step-by-step explanation:

since you bought 25 on friday and 6 on tuesday, you can just add them up.

25+6=31

check your work.

31-6=25

i hope this !

-yand3r3

236 cm 16 time 12 = 192

6 times 7 = 42

192+42