What is the point slope form of y=1/2x-2

Point-slope form of a line: We need a point (x₀,y₀) and the slope "m";
y-y₀=m(x-x₀)

We have the next equation of line:
y=1/2 x-2  (slope-intercept form y=mx+b)

the slope of this line is 1/2  (m=1/2)
And any one point could be:
if x=0; then y=1/2 (0)-2=-2  (0,-2)

Therefore, we already have the point (0-,2) and the slope (m=1/2)
y-y₀=m(x-x₀)
y+2=1/2(x-0)

the point slope form of y=1/2 x-2; would be:
y+2=1/2(x-0)