What is the slope of the line represented by the equation 3x - 2y=5

m = 3/2

General Formulas and Concepts:

Pre-Alg

Equality Properties

Alg I

Slope-Intercept Form: y = mx + b

m - slope b - y-intercept

Step-by-step explanation:

Step 1: Define function

3x - 2y = 5

Step 2: Rewrite

Subtract 3x on both sides:          -2y = 5 - 3xDivide -2 on both sides:              y = -5/2 + 3/2xRewrite:                                        y = 3/2x - 5/2

Step 3: Identify

Slope m = 3/2

y-intercept b = -5/2

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12

The correct graph is the second one, with the points being at (-6,0), (2,0) and reaching down to (-2,-8)