What is the equation of the line that passes through the point (2,-4) and has a slope of 2

2x - y - 8 = 0

Step-by-step explanation:

x1 = 2

y1 = -4

m = 2

using the formula,

y-y1 = m(x-x1)

y+4 = 2(x-2)

y+4 = 2x - 4

y-2x+4+4 = 0

y-2x+8 = 0 (×-1)

2x - y - 8 = 0

Therefore the equation of the line is;

2x-y-8 = 0

answer: i guess 5 units?

step-by-step explanation:

{x = -1/2 ,   y = -1

step-by-step explanation:

solve the following system:

{2 x + y = -2

{10 x - 3 y = -2

in the first equation, look to solve for y:

{2 x + y = -2

{10 x - 3 y = -2

subtract 2 x from both sides:

{y = -2 x - 2

{10 x - 3 y = -2

substitute y = -2 x - 2 into the second equation:

{y = -2 x - 2

{10 x - 3 (-2 x - 2) = -2

10 x - 3 (-2 x - 2) = (6 x + 6) + 10 x = 16 x + 6:

{y = -2 x - 2

{16 x + 6 = -2

in the second equation, look to solve for x:

{y = -2 x - 2

{16 x + 6 = -2

subtract 6 from both sides:

{y = -2 x - 2

{16 x = -8

divide both sides by 16:

{y = -2 x - 2

{x = -1/2

substitute x = -1/2 into the first equation:

{y = -1

{x = -1/2

collect results in alphabetical order:

answer:   {x = -1/2 ,   y = -1