Let a, b, and c be constants, and let x be a variable. Which of the following is equivalent to a(x + b) < c when a < 0? (Rearranging Formulas) IMAGE BELOW :D

C

Step-by-step explanation:

We are given that:

Where a < 0.

To solve for x, we can divide both sides by a.

Since a < 0, a is negative. Hence, we must flip the inequality sign. This yields:

Subtract b from both sides. Hence:

In conclusion, our answer is C.

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.

answer: .64

step-by-step explanation

set up the formula for standard deviation for this set of numbers, then simplify