Need HELP RUNNING OUT OF TIMe :) Find the number.

the sum of the reversed number and the original number is 154. Find the original number, if the ones digit in it is 2 less than the tens digit.

86

Step-by-step explanation:

Let the number be 10x + y. So, the reversed number is 10y + x.

The sum is 154.

So, (10x + y) + (10y + x) = 154

⇒ 11x + 11y = 154

⇒ x + y = 14 (1)

Again, given that ones digit in the original number is 2 less than the tens digit.

So, y = x - 2 (2)

Now, solving (1) and (2) we get,

x + x -2 = 14

⇒ 2x = 16

⇒ x = 8

So, from equation (2), y = x - 2 = 8 - 2 = 6

Therefore, the original number is 10x + y = 10 × 8 + 6 = 86 (Answer)

answer: answer is c!

ok i got to organize the

3/15 and 12/55

3*

aha

3*4 equals 12 but not

a: no

b:

8/24 12/35

no

gautie

it's c

5/18 = 25/90

5*5=25

18*5 = 90

hope that you!

one more happy customer!

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step-by-step explanation: