Draw two isosceles triangles, ∆ABC and ∆ADC with common base AC . Vertexes B and D are in the opposite semi-planes determined by AC . Draw the line segment BD . Prove: AC ⊥ BD

Statement Reason

∆ABC and ∆ADC are isosceles Given

Segment AC is a common base

to ∆ABC and ∆ADC Given

Let K be the midpoint of the base

of segment AC, then BK is the

perpendicular bisector of segment perpendicular bisector of isosceles AC. triangle property.

Also, DK is the perpendicular

bisector of segment AC. perpendicular bisector of isosceles

triangle property

you just switch the numbers basically so it would be 3/17