Given z (x) = 6x^3 + bx^2 - 52x + 15, z (2) = 35, and z (-5) =0 algebraically determine all the zeros of z (x)

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2

what is the graph

step-by-step explanation:

if you need , reply with more info. u.

okay..i will pick 8!