A racecar driver is doing a time trial of a new car on a straight back. The car's distance from the timekeeper is represented by y=293x+50 where x is time in seconds and y is the distance from the timekeeper's position. How many feet from the timekeeper is the race car at the beginning?

50 feet

Step-by-step explanation:

The car's distance from the timekeeper us given by :

y = 293x+50

Where x is time in seconds and y is the distance from the timekeeper's position.

The general equation of a line is given by :

y = mx +c

On comparing, we get : c = 50

It means the timekeeper has covered 50 feets at the beginning.

the entire expression should be subtracted from 30. to subtract the quantity, distribute the negative sign, which changes the signs on the terms. so, the –2 changes to positive and gets added to 30 instead of subtracted from it.

hope this ! ^w^

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation: