One base of a trapezoid is five times as long as the other. The height is the average of the two bases. The area is 441 square units. Find the length of the longer base.

The length of the longer base he 35 units

Step-by-step explanation:

Here, we want to find the length of the longer base of the trapezoid

Mathematically, we can find the area using the formula;

1/2( a + b) h

where a is the shorter base

b is the longer base

h is the height

Let the shorter base be x

The other base is 5 times this length and that makes 5 * x = 5x

Height is the average of both bases;

(x + 5x)/2 = 6x/2 = 3x

Substituting these in the formula, we have ;

1/2(x + 5x)3x = 441

3x(6x) = 882

18x^2 = 882

x^2 = 882/18

x^2 = 49

x^2 = 7^2

x = 7

But the longer base is 5x and that will be 5 * 7 = 35 units

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?