Find the equation of the line that passes through the points (8,-5) and (4,3) A. 2x + y = 11
B. x + y = -11
C. 5x + 8y = 4
D. 8x - 5y = 3

y=a(x - h)^2+k

standard form: y= - 1/2x^2+4x-5

vertex form: y= -1/2(x - 4)^2+3

slope m and y-intercept b

slope: -2

y-intercept:(0,11)

so the answer is A. your welcome

3100

step-by-step explanation:

b) k’(6, 4); l’(3, 3)

step-by-step explanation:

a 270° clockwise rotation maps every point (x, y) to (y, -x). (it negates the x-coordinate and then switches it and the y-coordinate.)

this means the endpoints of the side congruent to kl, k' and l', would be mapped as:

k'(-4, 6)→(6, 4)

l'(-3, 3)→(3, 3)