A 28-foot ladder is placed against a building and the top of the ladder makes a 27° angle with the building. How far away from the building is the base of the ladder? Write only the number rounded
to the nearest tenth of a foot.

Step-by-step explanation:

The set up is a right angles triangle

Given

The length of the ladder = 28 foot (hypoenuse)

theta = angle of elevation = 27 degrees

Required

Distance of the building from the base of the ladder (Adjacent)

According to CAH;

cos theta = adj/hyp

cos 27 = adj/28

adj = 28cos27

adj = 24.95 foot

Hence the length of the building from the base of the ladder is 24.95 feet

i believe the answer is the polygon, heptagon.