The price of Stock A at 9 A. M. was 13.54 $. Since then, the price has been increasing at the rate of 0.07$ each hour. At noon the price of Stock B was 14.29 $. It begins to decrease at the rate of 0.13$ each hour. If the two rates continue, in how many hours will the prices of the two stocks be the same? Whoever answer it CORRECT will get brainliest

hours from noon the stock prices will be same

Step-by-step explanation:

We can write equations for increasing stock and decreasing stock and find our answer.

Let number of hours be "t" for both to be same

For first, we can write:

13.14 + 0.06t

But, 2nd one starts from noon, so already 12pm - 9am = 3 hours gone, so stock A increased by 3 * 0.06 = 0.18, so we equation would be:

13.32 + 0.06t

Now, Stock B's equation [from noon]:

13.64 - 0.09t

Equate and solve:

In 2  2/15 hours, the prices will be same

hello from mrbilldoesmath!

answer:   x (x+6)^2, choice b

discussion:

factor x out of the equation:

x^3 + 12x^2 + 36x = x (x^2 + 12x + 36).

note that 6+6 = 12 and 6*6 = 36 so the above factors into:

x (x+6)^2

which is choice b

you,

mrb