Consider the polygon GEOM with coordinate G(0,-2), E(-1,2), 0(-5,1), M(-5, -6). If we rotate GEOM 90° clockwise about the origin, then reflect
over the y-axis, what are the coordinates of G"E"O"M"?
G(0, -2) G'(
) → G"(
E(-1,2) ► E'
.) EC
0(-5,1) ► O'C
) ► 0"
M(-5,-6) M'(___
.) - M"(_)

the anwser is d) 75°

step-by-step explanation:

simplifying

5(x + -6) = 2(x + 3)

reorder the terms:

5(-6 + x) = 2(x + 3)

(-6 * 5 + x * 5) = 2(x + 3)

(-30 + 5x) = 2(x + 3)

reorder the terms:

-30 + 5x = 2(3 + x)

-30 + 5x = (3 * 2 + x * 2)

-30 + 5x = (6 + 2x)

solving

-30 + 5x = 6 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-30 + 5x + -2x = 6 + 2x + -2x

combine like terms: 5x + -2x = 3x

-30 + 3x = 6 + 2x + -2x

combine like terms: 2x + -2x = 0

-30 + 3x = 6 + 0

-30 + 3x = 6

add '30' to each side of the equation.

-30 + 30 + 3x = 6 + 30

combine like terms: -30 + 30 = 0

0 + 3x = 6 + 30

3x = 6 + 30

combine like terms: 6 + 30 = 36

3x = 36

divide each side by '3'.

x = 12

simplifying

x = 12

this should .

step-by-step explanation:

graph using a few selected

x         y

-1       15

0         6

1         2.4

2       0.96