A waterfall has a height of 1700 feet. A pebble is thrown upward from the top of the falls with an initial velocity of  feet per second. The height of the pebble h in feet after t seconds is given by the equation h=-16t^2+24t+1700 . How long after the pebble is thrown will it hit the ground? PLEASE HEL

Step-by-step explanation:

The expression is given as:

Required

Determine how long it will hit the ground

When the pebble is on the ground, this implies that h = 0

So, we have that:

becomes

Reorder

Multiply through by -1

Solve using quadratic formula :

Where

So, we have:

or

or

or

But time can't be negative.

So:

Hence, it will take 11.085 seconds to hit the ground

80x^8−68x^6+16^5−20x^4−4x^3+8x^2

hope i'm right lol

e^-kt = n/n0 = 0.79  

-kt = ln 0.79  

t = - ln 0.79/0.0001  

= 2357 years

step-by-step explanation: