Graph the line with the equation y=5x-1

y-intercept: (0,-1)

x-intercept: (1,0)

Step-by-step explanation:

y = 5x − 1

Use the slope-intercept form to find the slope and y-intercept.

The slope-intercept form is  y = mx + b , where m is the slope and b is the y-intercept.

y = mx + b

Find the values of m and b using the form  y = mx + b

m = 5

b = −1

The slope of the line is the value of m, and the y-intercept is the value of b. Slope: 5

y-intercept: (0, −1)

Any line can be graphed using two points. Select two x values, and plug them into the equation to find the corresponding y values.

Find the x-intercept.

To find the x-intercept(s), substitute in 0 for y and solve for x.

0 = 5x − 1

x = 1/5

x-intercept(s) in point form.

x-intercept(s): ((1/5),0)

Find the y-intercept.

To find the y-intercept(s), substitute in 0 for x and solve for y.

y = 5 (0) − 1

y = −1

y-intercept(s) in point form.

y-intercept(s): (0, −1)

Create a table of the x and y values.

x | y

0 | -1

(1/5) |  0

Graph the line using the slope and the y-intercept, or the points.

Slope: 5

y-intercept: (0, −1)

x | y

0 | -1

(1/5) |  0

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.

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step-by-step explanation:

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