Sofia purchased a new car in 2007 for$34,000. The value of the car has been depreciating exponentially at a constant rate. If the value of the car was $16,200 in the year 2014, then what would be the predicted value of the car in the year 2021, to the nearest dollar?

$7,718

Step-by-step explanation:

Given that :

Cost of car in 2007 = $34000

Cost of car in 2014 = $16200

Predicted value of car in 2021

Lets obtain the percentage Depreciation (d) :

Worth (A) of car in 2014 = $16200

Time (t) = 2014 - 2007 = 7 years

Initial cost (I) = price in 2007

A = I(1 - d/100)^7

16200 = 34000( 1 - d/100)^7

16200 = 34000(1 - 0.01d)^7

(16200/34000)^1/7= 1 - 0.01d

0.8995 = 1 - 0.01d

0.01d = 1 - 0.8995

d = 0.1005 /0.01

d = 10.05

Value of car in year 2021:

t = 2021 - 2007 = 14 years

A = I(1 - 10.05/100)^14

A = 34000(1 - 0.1005)^14

A = 34000(0.8995)^14

A = 34000 * 0.2269950

A =7717.83100

Approximate worth = $7718

-2 is the right

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)