Please show me the steps to solve this problem

This is a pre-algebra problem. I'll go through the steps with you. If you don't get it, don't be afraid to ask!

Step One - Cross Multiply

These are fractions, but that doesn't mean you have to add them. Fractions are just the numerator divided by the denominator. So to 'remove' the 9, multiply both sides by 9. To 'remove' the 6, multiply both sides by 6. (We multiply both sides of the equation by the same number because we need to make each side the same). Note that when you multiply both sides by 9 or 6, you have to multiply the whole part.

(2x+1)×6 = (1-1)×9

Distribute.

12x+6 = 9-9

Step Two - Solve the Equation

So we are left with this equation after cross multiplying:

12x+6 = 9-9

First, we can start by subtracting 9 from 9, because those are the same types of numbers.

12x+6 = 0

Now, we have to 'remove' the 6. We can do that by subtracting each side by 6.

(12x+6)-6 = 0-6

12x = -6

Now we are left this this.

We need to 'remove' the 12 now, so we can isolate the x. Since 12 is multiplied to x, we divide each side by 12.

(12x)÷12 = -6÷12

We get x = -1/2

x = -1/2 or -0.5

Hope this helped!

the answer is c

step-by-step explanation:

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3