The larger of two numbers is four times the smaller number, and their difference is 18. Find the two numbers.

x = 12 , y = 10

Step-by-step explanation:

Let x , y are two numbers.

x > y

1 ) Three times the greater is 18 times their

difference

3x = 18( x - y )

x = 6( x - y )

x = 6x - 6y

6y = 5x

y = 5x/6 ——-( 1 )

2 ) 4 times the smaller is 4 less than twice

the sum of the two

4y + 4 = 2 ( x + y )

2y + 2 = x + y

y = x -2 ——( 2 )

From ( 1 ) and ( 2 ) ,

5x/6 = x -2

( 5x /6 ) - x = -2

( 5x - 6x ) /6 = -2

-x = -12

x = 12

Put x = 12 in equation ( 2 ) , we get

y = 12 - 2

y = 10

Therefore ,

x = 12 , y = 10

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0

i think it is c, not positive though

step-by-step explanation: