If RT bisects SU, find each measure ST, RU, SV, SU,

A bisector divides the lines it bisects into equal segments

The measures of ST, RU, SV, SU are 23, 8, 10 and 5 respectively

From the diagram, we have:

Because RT bisects SU, then:

So, we have:

Also, we have:

So, we have:

Also, we have:

Lastly, we have:

Hence, the measures of ST, RU, SV, SU are 23, 8, 10 and 5 respectively

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ST = 23

RU = 8

SV = 5

SV = 10

Step-by-step explanation:

Use the knowledge of the properties of a kite to find the measure of ST, RU, SV, and SU as shown below:

✍️Recall: Each pair of adjacent sides of a kite are congruent/equal.

ST and TU are a pair of adjacent sides.

TU = 23

✅Therefore, ST = 23.

RU and RS are a pair of adjacent sides.

RS = 8

✅Therefore, RU = 8.

✍️ Recall: the longer diagonal of a kite bisects the shorter one. This means RT divides SU into two equal parts, namely SV and UV.

Since UV = 5, therefore,

✅SV = 5

SU = UV + SV

✅SV = 5 + 5 = 10

853.3

step-by-step explanation:

explanation:

previous steps have made pa≅ pb ≅ st ≅ su. setting the compass width to ab allows you to make tu the same length. then δstu ≅ δpab by the sss congruence postulate, and ∠p ≅ ∠s by the reason cpctc.