Suppose a variable has population mean =39.45 and standard deviation =2.67 . Determine the standard error (SE) of the sampling distribution of the mean of a simple random sample of size =12 . Give your answer precise to two decimal places. SE = ?

it could 14.28 but if its not that one then it has to be the 17 one. hope this ! : )

step-by-step explanation:

im not sure

step-by-step explanation:

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

there were a lot of them but the first one to pop up on a google search was bts