what is the point slop equation of the line through the points (-5,5) that is perpendicular to the line whose equation is 5x=3y

y - 5 = - (x + 5)

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

Given

5x = 3y , that is

3y = 5x ( divide both sides by 3 )

y = x ← in slope- intercept form

with slope m =

Given a line with slope m then the slope of a line perpendicular to it is

= - = - = - and (a, b) = (- 5, 5), then

y - 5 = - (x - (- 5) ), that is

y - 5 = - (x + 5) ← equation of perpendicular line

5x + 5

step-by-step explanation:

you should always add the diagrams and graphs we cannot see. this particular question is kind of borderline because we can make a graph for you.

(f + g)x = -x^2 +3x + 5 + x^2 + 2x

(f + g)x = 5x + 5

the graph of z = 5x + 5 is shown below. always use desmos when in doubt.