Find the equation of a line with the given points. (put your answers in the form y = mx
b.) (6, 1) (5, 4) user: find the equation of a line with the given points. (put your answers in the form y = mx
b.) (8, 1) (7, 9)

Given two points (x₁,y₁) and (x₂,y₂), the slope of the line passes throught of these points will be:

m=(y₂-y₁)/(x₂-x₁)

If we want to find the equation of a line, we only need a point  (x₀,y₀) and the slope:
Point-slope form:    y-y₀=m(x-x₀)

a)
(6,1)
(5,4)
1)we find the slope of the line passes through these points.
m=(4-1)/5-6)=3/-1=-3

2)We find the equation of the line:
We can choose either points of two points
if we chose the point (5,4)
y-y₀=m(x-x₀)
y-4=-3(x-5)  (point-slope form)
y-4=-3x+15
y=-3x+19  (slope intercept form)

the equation would be: y=-3x+19

b)
(8,1)
(7,9)
m=(9-1)/(7-8)=8/-1=-8

y-y₀=m(x-x₀)
y-1=-8(x-8)
y-1=-8x+64
y=-8x+64+1
y=-8x+65

y=-8x+65