An astronaut weighs 168 lbs on earth and 28 lbs on the moon. Kristine weighs 108 lbs on earth. How would Kristine find out how much she would weigh on the moon? F divide 168 by 28 and divide 108 by the answer G subtract 28 from 168 and subtract that amount from 108 H divide 168 by 108 and multiply the result by 28 J subtract 108 from 168 and divide by 28

On a certain portion of an experiment, a statistical test result yielded a p-value of 0.21. what can you conclude? 2(0.21) = 0.42 < 0.5; the test is not statistically significant. if the null hypothesis is true, one could expect to get a test statistic at least as extreme as that observed 21% of the time, so the test is not statistically significant. 0.21 > 0.05; the test is statistically significant. if the null hypothesis is true, one could expect to get a test statistic at least as extreme as that observed 79% of the time, so the test is not statistically significant. p = 1 - 0.21 = 0.79 > 0.05; the test is statistically significant.

The associative, commutative, and distributive properties can be used on rational equations. true or false

Me because i don't understand how to do it.: )