A company has developed a training procedure to improve scores on the SAT. Following the training, 100 high school students take the SAT. The average math score is 517, with s = 90. Assuming µ = 500 for the math SAT, test the null hypothesis. Did training significantly improve scores (α = .05, directional)?

The calculated t-test = 1.717 < 1.6604 at 0.05 level of significance

Null hypothesis is accepted at 0.05 level of significance

A company has developed a training procedure is significantly improve scores

Step-by-step explanation:

Step(i):-

Given  sample mean (x⁻ )  = 517

sample standard deviation (s) =90

Mean of the Population (μ) =500

Null Hypothesis :- H₀ :   (μ) =500

Alternative Hypothesis : H₁ :  μ ≠ 500

Step(ii):-

Test statistic

                        t  =   1.717

Level of significance

                      ∝ = 0.05

                    t₀.₀₅ = 1.6604

The calculated t-test = 1.717 < 1.6604 at 0.05 level of significance

Conclusion:-

Null hypothesis is accepted at 0.05 level of significance

A company has developed a training procedure is significantly improve scores

answer: yes, he is correct

step-by-step explanation: 10x-1=59

                                              1-1=0     59+1=60

60/10=x=6

im not sure

step-by-step explanation: