You are running a concession stand at a basketball game. You are selling hotdogs and sodas. Each hotdog cost $1.50 and each soda cost $0.50. At the end of the night you made a total of $78.50. You sold a total of 87 hotdogs and sodas combined. How many hotdogs did you sell?

35 hotdogs

Step-by-step explanation:

You are running a concession stand at a basketball game. You are selling hotdogs and sodas.

Let the number of hot dogs be represented by x

The number of soda be represented by y

You sold a total of 87 hotdogs and sodas combined

x + y = 87

x = 87 - y

Each hotdog cost $1.50 and each soda cost $0.50. At the end of the night you made a total of $78.50.

Hence we have the equation:

$1.50 × x + $0.50 × y = $78.50

1.50x + 0.50y = 78.50

Substitute 87 - y for x

1.50(87 - y) + 0.50y = 78.50

130.5 - 1.50y + 0.50y = 78.50

Collect like terms

- 1.50y + 0.50y = 78.50 - 130.50

-1.00y = -52

y = -52/-1

y = 52 sodas

How many hotdogs did you sell?

Using the equation:

x = 87 - y

x = 87 - 52

x = 35 hotdogs

Hence, you sold 35 hotdogs

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option