A car covered a certain distance at a speed of 24 mph. While returning, the car covered the same distance at a speed of 16 mph. What was the average speed of the car for the entire journey? please healp

(96/5) mph, or 19.2 mph

Step-by-step explanation:

Average speed = (total distance traveled) / (total time elapsed)

Here we need to calculate the two elapsed times (going and returning)

Going:  t1 = d/(24 mph)

Returning:  t2 = d/(16 mph)

Less time is required for the outward bound trip.

                                                                            16d + 24d

Total time elapsed:  t = t1 + t2 = d/24 + d/16 = = (5/48)*d hr

                                                                                 16*24

Thus, the average speed is (total distance traveled) / (total elapsed time)

                                2d

which here is = (96/5) mph, or 19.2 mph

                             (5/48)d

4x and 6y

im not sure though