Lina and Josh each made a factor tree to find the prime factorization of 126. Lina’s Solution Josh’s Solution
2 factor trees. Alina's factor tree of 126. 126 branches to 3 and 42. 42 branches to 6 and 7. 6 branches to 2 and 3. The equation is 126 = 2 times 3 squared times 7. Josh's factor tree of 126. 126 branches to 2 and 63. 63 branches to 9 and 7. The equation is 126 = 2 times 7 times 9.

Which statement explains the accuracy of the students’ work?
Lina’s solution is correct because it expresses 126 as a product of prime factors.
Josh’s solution is correct because the factor tree of every even number must begin with 2 and its factor pair.
Both solutions are correct because they both express 126 as a product of factors.
Neither solution is correct because the factor tree should have begun with 6 and 21.

step-by-step explanation:

part a. the differences are decreasing, so we know the sequence is not arithmetic. the ratios are constant (=3/4), so we know the sequence is geometric.

part b. from part a, we know the common ratio is 3/4, so each term is 3/4 of the one before. the initial term is the number of gallons at h=1.

g[h] = (3/4)·g[h-1]

g[1] = 384 . . . . initial value required for a recursive definition

part c. the general formula for a geometric sequence is

a[n] = a[1]·r^(n-1)

we have a[1] = 384, r = 3/4, and the term number given by h. the formula that follows is

g[h] = 384·(3/4)^(h-1)

part d. filling in the value and doing the arithmetic, we have

g[12] = 384·(3/4)^11 ≈ 384·0.042235136 ≈ 16.2183 . . gallons

part e. each gallon is 4 quarts, so

16.2183 gal × 4 qt/gal = 64.8732 qt

could u provide us some answer choices or hmm idk maybe a table for us to anser with ? ?

im not sure what this means: mc011-7.jpg

step-by-step explanation: