Simplify 6z^-7 (2) x² (4) ^4x^-4

Step-by-step explanation:

First, subtract  

7

from each side of the equation to put the equation in standard form:

x

2

+

4

x

+

4

−

7

=

7

−

7

x

2

+

4

x

−

3

=

0

We can now use the quadratic formula to find the solutions for  

x

. The quadratic formula states:

For  

a

x

2

+

b

x

+

c

=

0

, the values of  

x

which are the solutions to the equation are given by:

x

=

−

b

±

√

b

2

−

(

4

a

c

)

2

⋅

a

Substituting:

1

for  

a

4

for  

b

−

3

for  

c

gives:

x

=

−

4

±

√

4

2

−

(

4

⋅

1

⋅

−

3

)

2

⋅

1

x

=

−

4

±

√

16

−

(

−

12

)

2

x

=

−

4

±

√

16

+

12

2

x

=

−

4

±

√

28

2

x

=

−

4

±

√

4

⋅

7

2

x

=

−

4

±

√

4

√

7

2

x

=

−

4

±

2

√

7

2

x

=

−

4

2

±

2

√

7

2

x

=

−

2

±

√

7

Or

x

=

−

2

+

√

7

and  

x

=

−

2

−

√

7

step- i d k and i d c : )

you: : 0

bye