You are a landscaper, and you are designing a fence to enclose part of a yard. The section to be enclosed is rectangular and has a width of 21 feet and a length of 38 feet. What length of fence, in feet, will you need to enclose this part of the yard? 59 60 118 120 798

If you draw this out, you can see that total fence equation will be:

2L + 4W = 1200

Simplify, divide by 2

L + 2W = 600

L = (600-2W)

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Area;

A = L*W

Substitute (600-2W) for L:

A = (600-2W)*W

A = -2W^2 + 600W; a quadratic equation

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The dimension that will produce the greatest area will be the "axis of symmetry

which is: x = %28-b%29%2F%282a%29

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In this equation a=-2, b=600

W = %28-600%29%2F%282%2A-2%29

W = %28-600%29%2F%28-4%29

W = +150 ft is the width

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Find the length

L = 600 - 2(150)

L = 300 ft is the length

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We can say the a field 300 by 150 gives he greatest area

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This illustrated on a graph where y axis is the area and x axis is the width:

Step-by-step explanation:

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step-by-step explanation:

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step-by-step explanation: