Mathematics, 18.11.2020 21:50 tsimm3618

A soccer ball is kicked from the ground at a 45° angle with an initial velocity of 40 feet per second. The height of the soccer ball above the ground is given by the equation H(x) = -0.0128x2 + x, where x is the
horizontal distance the ball travels.
a. What is the maximum height the ball reaches?

Answers: 1

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A soccer ball is kicked from the ground at a 45° angle with an initial velocity of 40 feet per second. The height of the soccer ball above the ground is given by the equation H(x) = -0.0128x2 + x, where x is the horizontal distance the ball travels. a. What is the maximum height the ball reaches?

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Another question on Mathematics

A soccer ball is kicked from the ground at a 45° angle with an initial velocity of 40 feet per second. The height of the soccer ball above the ground is given by the equation H(x) = -0.0128x2 + x, where x is the
horizontal distance the ball travels.
a. What is the maximum height the ball reaches?