10 – 5y = 2(14-y)
solve. show ur work

The answer is y= −6

Step-by-step explanation:

Let's solve your equation step-by-step.

10−5y=2(14−y)

Step 1: Simplify both sides of the equation.

10−5y=2(14−y)

10+−5y=(2)(14)+(2)(−y)(Distribute)

10+−5y=28+−2y

−5y+10=−2y+28

Step 2: Add 2y to both sides.

−5y+10+2y=−2y+28+2y

−3y+10=28

Step 3: Subtract 10 from both sides.

−3y+10−10=28−10

−3y=18

Step 4: Divide both sides by -3.

−3y/−3=18/−3

y=−6

y=−6

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)