Skip and Jena are selling raffle tickets to raise money for new basketball uniforms. Skip sold 2 tickets for every 7 tickets that Jena sold. If Jena sold 63 tickets how many did Skip sell? Use a double number line and equivalent ratios to justify your answer. please use a double number line to show your work

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Let J represent the number of tickets Jose sells. Let M represent the number of tickets Mark sells. Make equations, if Mark sells 15 more tickets than Jose, the equation is J+15=M. Because we know that in between both of them they sell 63 raffle tickets, then M+J=63. Now plug in the value of M (J+15) into M+J=63. And you get (J+15)+J=63, which is 2J+15=63. Subtract 15 from both sides and get 2J=48. Now divide 48 by 2, J=24. So now you know Jose sold 24 tickets, and to find how many Mark sold, plug in 24 into J+15=M and get 24+15=M where M is 39. Now check, 24+39=63. So Mark sold 39 tickets and Jose sold 24.

Step-by-step explanation:

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)