Please help Which of the following is the equation of the line that is parallel to the graph of y = 5x + 7 and has y-intercept at (0, -2)

y=−15x−2

y is equal to negative 1 fifth x minus 2

y=5x−2

y is equal to 5 x minus 2

y=−2x+7

y is equal to negative 2 x plus 7

y=5(x+2)

y=-15x-2

Step-by-step explanation:

Please help

Which of the following is the equation of the line that is parallel to the graph of y = 5x + 7 and has y-intercept at (0, -2)

y=−15x−2

y is equal to negative 1 fifth x minus 2

y=5x−2

y is equal to 5 x minus

560

hope this : )

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204