Carlos observes a ship from a cliff. The ship is 1.3 km away from the bottom of the cliff. Given that the height of the cliff is 150m, find the angle of depression of
the ship.

Step-by-step explanation:

Step one:

given

The distance of the ship from the base= 1.3km

Height of the cliff= 150m= 1.5km

Step two:

Required

angle of depression

Applying SOH CAH TOA

The opposite is to the angle of depression is the height which is 1.5km

The distance of the ship from the foot of the cliff is the adjacent  which is 1.3km

Tan ∅=Opp/Adj

Tan ∅=1.5/1.3

∅=Tan-1 1.5/1.3

∅=Tan-1 1.153

∅=49.06

49° approx.