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Given log7⁡3≈0.5646 and log7⁡16≈1.4248, evaluate the expressions.

7⁡3≈0.5646 and log7⁡16≈1.4248

C=  5 9  (F−32)

A temperature increase of 1 degree Fahrenheit is equivalent to a temperature increase of  5 9  degree Celsius.

Step-by-step explanation:

A temperature increase of 1 degree Fahrenheit is equivalent to a temperature increase of  5 9  degree Celsius.

7⁡16≈1.4248

Step-by-step explanation:

 Hope this helps :)

-Danny

hc ghfrfgb

step-by-step explanation:

gedfgb nbgfrezrdfgbn bgfderdfgbvn bvfdsvcb bvfdfgb gfdgb gfr

see explanation

step-by-step explanation:

a

(6r + 7) + (13 + 7r) ( remove brackets and collect like terms )

= 6r + 7 + 13 + 7r

= 13r + 20

b

remove brackets and collect like terms

13 - r - 1 + r

= 12 - r

c

remove brackets and collect like terms

= - 8 - r + 2r - 4

= - 12 + r

d

remove brackets and collect like terms

= 7r - - - 6r

[-   - = - - = - ]

= r -