Write an equation of the line that is parallel to 3x + y = 7 and passes through the point (6,4).

y = -3x + 22

Step-by-step explanation:

To write the equation we need to know the slope and the y-intercept. We know that when two lines are parallel their slopes are equal. So, let's convert the given equation into slope-intercept form:

3x + y = 7

y = 7 - 3x

The slope of the line is -3 for both equations.

We can use the slope and the given point (6, 4) to find the y-intercept:

y = -3x + b

4 = -3(6) + b

4 = -18 + b

22 = b

The y-intercept of the equation is 22.

Now that we know the slope and the y-intercept, we can write our equation:

y = -3x + 22

Hope this helps :)

here you hope this .

step-by-step explanation:

hypotenuse = √(15² + 8²)

=  √(225 +64)

=  √(289) = 17

sin(x) = cos(y) = 8/17

they are identical so long as you are doing the sine of one angle and the cosine of the only other angle that isn't the right angle.

may i see the picture? it would a lot, xox