Triangles PQR and RST are similar right triangles. Which proportion can be used to show that the slope of LaTeX: \overline{PR}P R ¯ is equal to the slope of LaTeX: \overline{RT}R T ¯? Group of answer choices LaTeX: \frac{-4-\left(-3\right)}{-7-7}=\fr ac{2-\left(-5\right)}{-4-3}− 4 − ( − 3 ) − 7 − 7 = 2 − ( − 5 ) − 4 − 3 LaTeX: \frac{3-7}{-4-\left(-7\right)}=\fra c{-5-3}{2-\left(-4\right)}3 − 7 − 4 − ( − 7 ) = − 5 − 3 2 − ( − 4 ) LaTeX: \frac{-4-\left(-7\right)}{3-7}=\fra c{2-\left(-4\right)}{-5-3}− 4 − ( − 7 ) 3 − 7 = 2 − ( − 4 ) − 5 − 3 LaTeX: \frac{3-\left(-4\right)}{7-\left(-7 \right)}=\frac{-5-2}{3-\left(-4\rig ht)}

Question:

Triangles PQR and RST are similar right triangles.  Which proportion can be used to show that the slope of PR is equal to the slope of RT?

Step-by-step explanation:

See attachment for complete question

From the attachment, we have that:

First, we need to calculate the slope (m) of PQR

Here, we consider P and R

Where

becomes

--------- (1)

Next, we calculate the slope (m) of RST

Here, we consider R and T

Where

becomes

---------- (2)

Next, we equate (1) and (2)

From the list of given options (see attachment), option A answers the question

constant acceleration- a

constant velocity- c

no velocity or acceleration- b

explanation:

for body moving with a constant acceleration, the rate of change of displacement changes over time. this is proven by the increasing gradient of the curve (a) against time.

a body that is moving at constant velocity covers equal distances over equal periods of time, thus the straight line with a constant gradient c.

a stationary body   covers no displacement as time elapses. thus the flat line with   zero gradient.