The weather outside was very abnormal. The temperature started out at 6°C in the morning and went to -13°C at noon. It stayed at that temperature for six hours and then rose 10°C. How far below the freezing point (0°C) was the temperature at 6 p. M.? *

At 6 pm, the temperature was 13°C below the freezing point

Step-by-step explanation:

Let us first express the information clearly to determine the temperature at 6 p.m:

The temperature in the morning = 6°C

the temperature at noon (12pm) = -13°C

It stayed at that temperature for six hours; this means that the temperature from 12 noon to 6 pm = -13°C

∴ Temperature at 6 pm = -13°C

Next let us calculate how far -13 is, below freezing point (0)

Difference = 0 - (-13)

= 0 + 13 = 13°C

Therefore, at 6 pm, the temperature was 13°C below the freezing point

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what relationship between ideas is shown in the text above?

question 1 options:

location of events

similarity of events

timing of events

examples of an idea

step-by-step explanation:

hi! i think the answer is 1/2 : )