What is the solution to −2(2x−6)+4x≤−8x+4(−2x−5) ?

x<_-2 ( x is less than or equal to -2)

Step-by-step explanation:

First remove opposites and collect like terms so it will be -4x+12+4x<_-8x-8x-20.

Then move them to be 12<_-16x-20.

Move -16x to the left and the 12 to the right to combine it with -20 to become -32.

You are now left with 16x<_-32.

Divide both sides by 16 to get x<_-2.

Hope this helped :) btw <_ is less than or equal to i just dont know how to put the sign on top of the underscore :/

1. minimum

2. 6400

3. eight

hope this !