Given Δ
Q
R
S
≅
Δ
T
U
V
,
Q
S
=
3
v
+
2
and
T
V
=
7
v
−
6
, find the length of QS and TV.

The length of the segment QS is 8 units and the length of the segment TV is 8 units and this can be determined by using similar triangle properties.

Given :

The following steps can be used in order to determine the length of QS and TV:

Step 1 - According to the given data, the triangle QRS is congruent to triangle TUV.

Step 2 - So, the length of the segment QS is equal to the length of the segment TV.

QS = TV

Step 3 - Substitute the values of QS and TV in the above expression.

3v + 2 = 7v - 6

7v - 3v = 6 + 2

4v = 8

v = 2

Step 4 - The length of the segment QS and TV is:

QS = 3(2) + 2 = 6 + 2

QS = 8

TV = 7(2) - 6 = 14 - 6

TV = 8

For more information, refer to the link given below:

link

QS = TV = 8

Step-by-step explanation:

As ΔQRS ≅ ΔTUV ,

QR = TU ; RS = UV ; QS = TV ( Corresponding sides of 2 congruent triangles are equal )

As QS = TV ,

QS = 3v + 2 = 3×2 + 2 = 8

TS = 7v - 6 = 7×2 - 6 = 8

step-by-step explanation:

abc

this answer is !