Zeros : x=-2 multiplicity 2 X= 1 multiplicity 1

Determine the equation of least degree of a polynomial given the following zeros and their multiplicities (standard form)

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47

the anwser is d) 75°

step-by-step explanation:

the answer is c just got it on ed

step-by-step explanation:

the answer is 1/4

step-by-step explanation: