(8 - h)(jh + jh) use h=-1 and j=5

I would do this but im kind of confused please help

-90

Step-by-step explanation:

(8-h)(jh+jh)

Since the values of h and j are given, we use substitution to replace the variables with their number values

(8-(-1))(j(-1)+j(-1) replaced all the h with -1

(8-(-1))((5)(-1) + (5)(-1)) replaced all the j with 5

Then we solve inside the parenthesis first

(8+1)(-5+(-5))

(9)(-10)

Then, multiply

-90

x=30

step-by-step explanation: