Given: MO bisects ∠PMN and OM bisects ∠PON Prove: ΔPMO ≅ ΔNMO Statements Reasons 1. MO bisects ∠PMN 2. ∠PMO ≅ ∠NMO 3. MO ≅ MO 1. Given 2. Definition of angle bisector 3. Reflexive property 4. OM bisects ∠PON 5. ∠POM ≅ ∠NOM 6. ΔPMO ≅ ΔNMO 4. Given 5. Definition of angle bisector 6. ?

From the given statements and reasons, we can deduce that ΔPMO ≅ ΔNMO because; it fulfils the ASA Congruence postulate.

We are given;

1) MO bisects ∠PMN

2) ∠PMO ≅ ∠NMO which means that ∠PMO is congruent to ∠NMO

3) MO ≅ MO

4) OM bisects ∠PON

5) ∠POM ≅ ∠NOM which means that ∠POM is congruent to ∠NOM

6) ΔPMO ≅ ΔNMO

     Now, from all the statements given, we can see that two corresponding angles of both ΔPMO and ΔNMO are equal.

We also see that they share a common side which is MO.

Thus, we can say that both triangles have two corresponding sides that are equal and a corresponding included angle that is also equal.

     In conclusion, ΔPMO ≅ ΔNMO because it fulfils the ASA Congruence postulate.

Read more at; link

for any of you who need the translation here it is

step-by-step explanation:

find the angular size of the equatorial radius of the earth, if the horizontal parallax of the sun

the answer is a

step-by-step explanation: