Miranda has been offered two jobs. The pay at job A would be $750 per month plus 15% of the value of the merchandise she sells. Job B offers $675 per month plus 20% of the value of the merchandise she sells. What value of merchandise must she sell in order to make more money at job B than job A? Which of the following best represents this situation? A. 750 + 0.15x = 675 + 0.20x

B. 750 + 0.20x = 675 + 0.15x

C. 750 + 0.15x > 675 + 0.20x

D. 750 + 0.15x < 675 + 0.20x

x - would be the total value of merchandise sold

y - would be her take home pay would be

Job A: y = 0.15x + 750

Job B: y = 0.20x + 675

We want to know when job B's pay will be larger than job A's pay. So set the expression for job B larger than job A, solve for x

0.20x + 675 > 0.15x + 750

0.20x - 0.15x > 750 - 675

0.05x > 75

x > 75/0.05

x > 1500

Miranda must sell more than $1500 worth of merchandise to have

C would be your best answer, correct me if i am wrong.

Step-by-step explanation:

stew reads at the fastest rate of 265 words per minute.

step-by-step explanation:

it's a given that felicia reads at 260 word per minute and on connie's graph we can see that she reads 200 words per minute. since stew's table tells us that he read 795 in 3 minutes, we can divide 795 by 3 to find out how many words he reads per minute.

795/3 = 265

stew reads 265 words per minute - he reads at the fastest rate since felecia reads at 260 words per minute and connie reads at 200 words per minute.

stew (265) > felecia (260) > connie (200)

whole numbers.

step-by-step explanation:

we are given the average monthly rainfall (in millimeters) model r(m) for the years 1900-2009 as a function of the month number m.

as we can see m is taken for the number of months for years 1900-2009.

we know that number of months can't be a negative number or decimal number or a fraction.

so, the number of months could be only positive whole numbers.

therefore, whole numbers is more appropriate for the domain of r.