Suppose a box contains 3 defective light bulbs and 12 good bulbs. Two bulbs are chosen separately from the box without replacement. What is the probability that one of two bulbs drawn is defective and one is not?

Step-by-step explanation:

Given

Represent Defective Bulbs with D and non good bulbs with G

The probability that one is defective and the other is not can be represented with: (D and G) or (G and D)

Which means that the defective is selected first, then the good one or the good one is selected first, then the defective one.

This is then calculated as:

We used Total - 1 on second selections because it is a probability without replacement

distance covered by pamela in 9 l of fuel = 99km

let us apply unitary method here.

distance covered by pamela in 1 l of fuel =99/9 =11 km

now let us find distance covered by pamela if she has 12 l of fuel.

distance covered in 12 l = distance covered in 1 l of fuel * 12

we know that distance covered by here in 1 l is 11 km.

so distance covered in 12 l of fuel = 11*12 = 132 km.

i think it is everything has to equal 180 so, if i correct 4=c. 6=d. 8=a. 7=b. and the last question would be c. because they are parallel lines and they are congruent.

step-by-step explanation:

the reason everything has to equal to 180 is because that is how it works. i'm guessing that is its rule. 4 and 8 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 6 and 7 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 60+60 is 180. so, now you have your answer