Suppose 40% of the population of pre-teens have a TV in their bedroom. If a random sample of 500 pre-teens is drawn from the population, then the probability that between 36% and 44% of the pre-teens have a TV in their bedroom is: a) 0.9644
b) 0.4644
c) 0.0356
d) 0.9328
e) 0.0712

0.9328

Step-by-step explanation:

The mean of the sampling distribution is equal to

up = p = 0.40

The standard deviation = √pq/n

= √0.40x0.60/500

= √0.00048

= 0.0219

We compute the z values for the probability of 36% and 44%

When p = 0.36

z = 0.36-0.40/0.0219

= -1.83

When p = 0.44

z = 0.44-0.49/0.0219

= 1.813

From the standard normal distribution table. The probability associated with z values from Which we subtract the probability

P(0.36<=p<=0.44)

= P(-1.83<=z<=1.83)

P(z<=1.83)-p(z<=-1.83)

= 0.9664-0.0336

= 0.9328

Therefore the answer is 0.9328

y do u put "subscirbe to ence" on a app for ppl who need with their work?

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."