Write the equation of a line that passes
through (-3,-8) and (3, 10).

y=3x+1

Step-by-step explanation:

The equation will most likely be in slope-intercept form which is

y=mx+b

(m) is the slope,

(b) is the y intercept

First we must find the slope. The formula for slope is (y1-y2)/(x1-x2)

Which means we take the (y) of the second given point and subtract the (y) if the first given point, then divide that by the (x) of the second given point minus the (x) of the first given point.

(10-(-8)/3-(-3)

18/6

Simplify

3/1

3, our slope is 3.

Now we can put this into our formula

y=3x+b

To find the y intercept we just apply one of the given points. (I'll use (3, 10) but either of them would work.

10=3(3)+b

Now solve

10=9+b

Subtract 9 from each side

1=b

Now we put our slope and y intercept into our formula

y=3x+1.

Hope this helps! If you have any questions on how I got my answer feel free to ask. Stay safe!

y -5 = (-1/4)(x + 8)

step-by-step explanation:

other answer is correct. i had used the radius of the radius somehow. a website: