I need help with this question. I am very confused.

44°

Step-by-step explanation:

First, m ∠ D=112° and  ∠ABC are congruent in a parallelogram and congruent angles have same measure so m ∠ ABC=112° as well

Second, ∠ABC and ∠CBE are supplementary angels so they add up to 180° because adjacent angles that form a line are suplementary, therefore, ∠CBE=180-112=68°

Third, ∠CBE≅∠BCE because the ΔCEB is isosceles since is given CE≅BE and base angles of isosceles triangles are congruent.

Congruent ∠s have same measure so m∠BCE =68° as well

Last sum of angles in a Δ is 180° so from  ΔCEB we have

m ∠E = 180-68-68=44°

4x and 6y

im not sure though

you can't solve x because it is 2 linear equation and you only have one equation